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Find vertex of x and y coordinate: f(x)=-2x^2+2x+3
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Do you mean find the x and y coordinates of the vertex?
yes sorry
\[x=\frac{-b}{2a}=\frac{-2}{4}=\frac{-1}{2}\]
Now plug -1/2 into the equation and find f(x). You will have your vertex.
\[2(\frac{-1}{2})^2+2(\frac{-1}{2})+3=\frac{1}{2}-1+3=\frac{5}{2}\]
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Vertex is (-1/2,5/2)
Wouldn't it be 1/2 and not negative?
Oh gees. Yes. I didn't see the negative sign in front of the 4. You'll have to recalculate. Sorry
in front of the 2.
No problem you have been a great help!
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