Find the number of years it will take for $27,000 to grow to $34262.61 at 6% interest compounded quarterly.
The following equation is the starting point: \[34262.61=27000(1+\frac{0.06}{4})^{x}=27000\times (1.015)^{x}\] Can yhou see what the next step should be?
So... 34262.61=(27405)^4x ??
no simplify the 1st equation \[34262.61 = 27000(1.015)^x\] then \[\frac{34262.61}{27000} = 1.015^x\] simplify the above equation do you know how to use logarithms...?
It's one of those things if I'm pointed in the right direction I rememebr the way :S
So am I just dividing both sides by 27000? And then logging it out?
yes... and with log laws \[\log(b^a) = alog(b)\] you need the above law for the right hand side... doesn't matter if its base 10 or base e logs and simplify the left hand side log (1.26899) = xlog(1.015) isolate x 1st then evaluate for the answer
when you find x.... it will be the number of quarters.... since the investment was compounded quarterly... divide by 4 for the years...
4?
yes... I got 16 quarters or 4 years
Yeah, x=16 So, I'm dividing that by four because its quarterly
thats correct.... hope it helps
It does...just need to keep doing them. The logs have me hung up. Thank you!
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