Question

solve by addition/elimination. Systems of Linear equations. Please explain as you help so that I can understand

6x-7y=-26
6x+5y=10

Answer 1

just subtract equation 2 .

Answer 2

when you use elimination method u will find that one of the two variables is eliminated and u get an equation with only one variable. that is
6x-7y=-26-(1)
6x+5y=10-(2)
when u subtract (1) from (2) u will get
6x+5y-6x+7y=10+26
12y=36
y=36/12
y=3.
Is that clear?

Answer 3

let me look....

Answer 4

hmm k. I will wait.

Answer 5

ok I have been doing this different. I got the same answer. y = 3 .... the way you did it is less confusing. Now I have another question

Answer 6

why did the signs change when you did that? from 10+26 instead of -10-26

Answer 7

u get -26-10 when u subtract (1) from (2).

Answer 8

After I find y im suppose to solve for x and then check my work by using one of the equations

Answer 9

so it would be 6x-7(3)=-26 .... so 6x=-26+21 which then makes x=5/6 but then when I check the work it does not add up .... so would I say it is not a solution and that is the answer?

Answer 10

x=-5/6
solve for x by putting the value of y in one of the eqns nd then check if the values satisfy both the eqns.

Answer 11

that's what I'm trying to do but it does not

Answer 12

never mind. it does work. I did not have the 5/6 as a negative. Now it works