Question

F(x)= 2x^2-2x, G(x)= 3x+3 H(x)= x-1
1.) f(x)-g(x)
2.) h(x) * g(x)
3.) f(x) / g(x)
4.) f(x) / h(x) simplified
5.) h(g(x))
6.) g(f(x))
show work

Answer 1

??

Answer 2

Basically, you take what function is represent, and do the calculation.

For example; 1.) \(f(x)-g(x)\)
We have \(f(x)= 2x^2-2x\), \(g(x)= 3x+3\)

Then \(f(x)-g(x)=(2x^2-2x)-(3x+3)\)

Answer 3

anwsers?

Answer 4

Do it yourself!

Answer 5

:P

Answer 6

3.) \(\large \frac{f(x)}{g(x)}\) For this one you have to factorize \(f(x)\)

Answer 7

arrrrrgh

Answer 8

For this one, \(h(g(x))\), usually, stuffs between parentheses is what you are going to replace x, in this case, replace x with \(g(x)\).

Answer 9

\(h(x)= x-1\);
\( g(x)= 3x+3\).

\(f(g(x))=(3x+3)-1=3x+2\)

Answer 10

Good luck! :D

Answer 11

1. (2x^2-2x)-(3x+3)
2. (x-1)(3x+3)
3. (2x^2-2x)/(3x+3)
4. (2x^2-2x)/(x-1)
5. (3x+3)-1
6. 3(2x^2-2x)+3

Simplify these from there.

Answer 12

:)

Answer 13

1.) -2x- 6x = -8?

Answer 14

There's no factoring in 1. All you need to to is subtract.
2x^2-2x-3x-3 (distributing the negative)
2x^2-5x-3

Answer 15

what DOES that mean?

Answer 16

What does what mean?

Answer 17

im stupid

Answer 18

Do you get how to do 1?

Answer 19

forget it

Answer 20

we will help you, you do need to respond back when asked to .