The local theater has 3 types of seats for Broadway plays: main floor, balcony and mezzanine. Main floor tickets are $37, balcony tickets are $31 and mezzanine are $27. One night sales are $56,591. There were 99 more main floor tickets sold than balcony and mezzanine combined. The # of balcony tickets sold is 400 more than 3 times the # of mezzanine tickets sold. How many of each type of tickets were sold?
Let x = Main floor tickets y = Balcony tickets z = Mezzanine tickets Now \[x=y+99\] \[y-400+3z\] \[37x+31y+27z=56591\] Solve for x y and z :)
can you help with that?
i just need the answer :/
Okey, lemme work it out
thanks buddyy!
Sorry my first equiation is wrong, its x=y+z+99
x=883 y=688 z=96
help with another?
Find if no solution, only one solution and if so, find the variables, or infinitely many solutions x-2y+2z=-7 6x-4y-z=-2 7x-6y+z=6
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