Question

Derivatives... Just want to check my answers...
1. Find y'(x) if xy=x^2+y^2+1
I got y'(x)=y-2x/(2y-x)

Answer 1

i think it's \(\frac{2x-y}{x-2y}\)

hmm...

SOLUTION:
xy' + y = 2x + 2y y'

xy' - 2y y' = 2x - y

y' (x -2y) = 2x - y

was that your solution??

Answer 2

yeah that's what I got, except I moved the (x-2y) to the other side :). thank you. So I guess I did it right then :p