Hey, what is integration of (-lnx) plz sent solution
What's the argument of the log? That is a natural log right?
use integration by parts\[u=\ln x\]\[dv=dx\](you can pull the negative sign out of the radical)
using integration by parts i think ..- xlnx+x+c
why is everyone so tempted to type the direct answer to this question? please do NOT type answers without explanation; the goal of this site is to teach and guide askers towards solutions only.
@muhammad_raza if you have any questions, or if you are unfamiliar with integration by parts, please say so
but when u=lnx then du=1/x.dx how can solve by using by part formula??
that is not how integration by parts works; you are trying to do a u-substitution
integration by parts involves u and dv
by the product rule\[(uv)'=u'v+v'u\]just looking at the differentials we get\[d(uv)=vdu+udv\]integrating the whole equation we get\[\int d(uv)=uv=\int vdu+\int udv\]solving for integral udv we get\[\int udv=uv-\int vdu\]which is the formula for integration by parts
this formula can be used on certain forms once we can break up the integrand into u and dv
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