Question

A company's revenue (in dollars) can be modeled by the function
R (p) = -15p^2 + 200p +10,000
where p is the price in dollars of the company's product. What price (in dollars) will maximize the revenue?

Round to the nearest penny.

Answer 1

Differentiate and equate to zero, and find 'p' from it.
That will be the value of 'p' for which the profit is maximised.

Answer 2

use the theorem that when x=(-b)/2a, y gets a max/min valve.
in this equation, the graph opens down, so it can have a max value where x=(-b)/2a=(-200)/(2*-15)=20/3
then substitude this x into the equation u can have a max result

Answer 3

Sorry I still don't understand

Answer 4

do u know that when x=(-b)/2a, y gets a max/min valve which is a theorem

Answer 5

yes

Answer 6

ok. can u find that this equation opens down, so it have a max value

Answer 7

yes

Answer 8

if u know the upper, then use x=(-b)/2a to get the value of x
and use that x to work out the max value