Question

solve the equation : a^3(b-c)(x-b)(x-c) +b^3(c-a)(x-c)(x-a) + c^3(a-b)(x-a)(x-b)=0

Answer 1

\[a^3(b-c)(x-b)(x-c) +b^3(c-a)(x-c)(x-a) + c^3(a-b)(x-a)(x-b)=0\]

Answer 2

\[a^3\frac{(b-c)}{(x-a)} +b^3\frac{(c-a)}{(x-b)} + c^3\frac{(a-b)}{(x-c)}=0\]

Answer 3

really i am being lazy
but
x=a=b=c can be the answer

Answer 4

and to unkle rhaukus
u cant divide an eq by smth which can be zero
still u seem to be the only one trying
respect

Answer 5

hmm, how are we going to fit the equation all on one line then?

Answer 6

This equation might be zero on expanding.

Answer 7

I am not really sure but

Answer 8

-sigh- No :/ Wolfram doesn't get me Zero