Chocolates costing $8 per pound are to be mixed with chocolates costing $3 per pound to make a 20 pound mixture. If the mixture is to sell for $5 per pound, how many pounds of each chocolate should be used? Which of the following equations could be used to solve the problem? 8x + 3x = 5(20) 8x + 3(20) = 5(x + 20) 8x + 3(20 - x) = 5(20)
I think B? @parthkohli
haha thanks.
Or! maybe A because I don't think you'd multiply the 3 by 20 .-. lol Parth will help us
okay, im so confused by this stuff lol
\[8x+3(20-x)=5\times 20\] is your equation
Satellite is here...I will shut up now.
thanks ya'll
we reason as follows: if you put the amount of $8 a pound chocolate as say \(x\) then since the total number of pounds is 20, the amount of $3 a pound chocolate must be \(20-x\)
\(x\) pounds at $8 per pound costs \(8x\) and \(20-x\) pounds at $3 costs \(3\times (20-x)\) for a total cost of \[8x+3(20-x)\]
wow your really smart
since you know the total cost is $5 times 20 = 100 you can set \[8x+3(20-x)=100\] and solve for \(x\)
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