Consider the line that passes through the point (-1, 6) and has a slope of -4. Part 1: Write the equation of this line using point-slope form. Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work.
But no dont show ALL work. Just help me understand it :) thanks
The equation of a line passing through \((x_1, y_1)\) and having a slope \(m\) is: \(\large \frac{y - y_1}{x - x_1} = m\) can you use this?
Part 1 1) use point -slope form y-y1=m(x-x1) so the equation would look like y-6=-4(x+1) Part Two 2) then the equation becomes y-6=-4x-4 3) add six to both sides to get y=-4x+2 Part 3 4) use the slope and y-intercept of the above equation 5) the standard from would look like y-2=x+0
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