The Royal Fruit Company produces two types of fruit drinks. The first type is 70% pure fruit juice, and the second type is 95% pure fruit juice. The company is attempting to produce a fruit drink that contains 80% pure fruit juice. How many pints of each of the two existing types of drink must be used to make 120 pints of a mixture that is 80% pure fruit juice?
put the number of pints of 95% fruit juice as say \(x\) then since the total is 120 the number of pints of 70% juice is necessarily \(120-x\) the total amount of fruit juice is therefore \[.95x+.70(120-x)\] and since you want this to be 80% of 120 = 96 set \[.95x+.70(120-x)=96\] and solve for \(x\) probably easier to multiply by 100 to rid yourself of the annoying decimals and write \[95x+70(120-x)=9600\]
so thats you find your first type how exactly would you change your equation to find the second type
you can either do this by hand, which is not that hard, \[95x+8400-70x=9600\] \[25x+8400=9600\] \[25x=1200\] \[x=1200\div 25=48\]so 48 pints of the 95% and therefore \(120-48=72\) pints of the 70%
i wouldn't change it at all. if i know the amount of 95% juice i also know the amount of 70% juice because they have to total 120 pints
i got x=48 :)
on the other hand you could start with \[.70x+.95(120-x)=96\] and get the amount of 70 juice it makes no difference
so first answer 95% second 70% ?
or do i give the whole numbers as answers
nvm
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