Question

Help.. Solve the system with the addition method:
-a/4-b/4=1

-a/3+b/6=1

Answer 1

\[-a/4-b/4=1\]
\[-(a+b)/4=1\]
\[-(a+b)=4\]
\[a+b=-4\]
\[b=-4-a\]

put the value of b in 2nd equation :
\[-a/3+b/6 = -a/3+(-4-a)\]
\[-a/3-4-a\]
\[(-a-3a-12)/3\]
\[-4a-12)/3\]
\[-4(a+3)/3\]
\[-4(a+3)/3 = 1\]
\[-4(a+3)=1\]
\[a+3=-1/4\]
\[a=-1/4-3\]
\[a=-13/4\]

Answer 2

b = -4-a
b = -4+13/4 = -3/4

Answer 3

for a it is -10/3 & for b it is -2/3

Answer 4

Simplifying first equation : a + b = -4
Second Equation : -2a + b = 6

Subtracting first and second equation : 3a = -10

Therefore, a = -10/3..

Like this, b = -2/3 is the right answer...