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the lines l and m have vector equations.r=i+j+k+s(i-j+2k) and r=4i+6j+k+t(2i+2j+k) respectively. find the equation of the plane containing l and m,giving your answer in the form ax+by+cz=d
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hmm, you might wanna wrap your "point" as well
?
l and m have direction vectors; and if they are to be in the same plane, they need to be parallel to a common vector, called a normal
cross your direction vectors for the normal
|dw:1339688705101:dw|
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|dw:1339688742834:dw|
|dw:1339688792748:dw|
do you know how to cross vectors?
|dw:1339688841387:dw|
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