Question

0 0 0 0 2
0 1 0 2 3
0 0 0 3 4
1 2 3 4 5
0 0 1 2 3

(A) –6 (B) –3 (C) 6 (D) 0

Answer 1

question?

Answer 2

actually i dont knw its frm which topic :(

Answer 3

matrices?

Answer 4

its written in that way as i copy

Answer 5

i think so !

Answer 6

how can u plss guide me on this ?

Answer 7

If a determinant:\[\text{Det}\left[\left( \begin{array}{ccccc} 0 & 0 & 0 & 0 & 2 \\ 0 & 1 & 0 & 2 & 3 \\ 0 & 0 & 0 & 3 & 4 \\ 1 & 2 & 3 & 4 & 5 \\ 0 & 0 & 1 & 2 & 3 \\ \end{array} \right)\right]=-6 \]

Answer 8

can u tell me how ?

Answer 9

http://www.analyzemath.com/Tutorial-System-Equations/determinants.html

Your expression was calculated using the Mathematica computer program. This is what computers are for.

Answer 10

you can swap rows; but each time you do, you need to alternate the sign of the resulting det

Answer 11

0 0 0 0 2 <
0 1 0 2 3
0 0 0 3 4
1 2 3 4 5 <
0 0 1 2 3


1 2 3 4 5
0 1 0 2 3
0 0 0 3 4 <
0 0 0 0 2
0 0 1 2 3 <


1 2 3 4 5
0 1 0 2 3
0 0 1 2 3
0 0 0 0 2 <
0 0 0 3 4 <

1 2 3 4 5
0 1 0 2 3
0 0 1 2 3
0 0 0 3 4
0 0 0 0 2 that was 3 swaps; -+-, the determinant
of this will be the negative of the original

Answer 12

since we have zeros all under the diagonal; the det is just the product of the diag

1.1.1.3.2 = 6

we want the opposite of 6: -6