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Mathematics 13 Online
OpenStudy (anonymous):

Cam someone explain, please?

OpenStudy (anonymous):

|dw:1339705711952:dw|

OpenStudy (anonymous):

What do you need to find?

OpenStudy (anonymous):

Based on wht I know... it should be 55. But that's not one of the options

OpenStudy (anonymous):

the measure of the numbered angle

OpenStudy (anonymous):

Is it a central angle?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Are the two arcs' measures 60?

OpenStudy (anonymous):

No, one is 60 and other's 50

OpenStudy (anonymous):

So the lines aren't diameters?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Okay. What are your options?

OpenStudy (anonymous):

And if they aren't diameters, then how is angle 6 a central angle?

OpenStudy (anonymous):

a. 115 b. 125 c. 120 d. 130

OpenStudy (anonymous):

How is angle 6 a central angle, then?

OpenStudy (anonymous):

It's not. I was just being silly

OpenStudy (anonymous):

Okay...well, I'm not sure then. Haven't done geometry in a while. Maybe someone like @eliassaab can help?

OpenStudy (anonymous):

oh, do you think you could help me with another?

OpenStudy (anonymous):

@thechocoluver445

OpenStudy (anonymous):

i'll try :)

OpenStudy (anonymous):

one second :)

OpenStudy (anonymous):

AE, right?

OpenStudy (anonymous):

I'm not sure. Let's see if the amazing campbell_st can confirm

OpenStudy (anonymous):

http://www.sparknotes.com/math/geometry2/theorems/section5.rhtml Theorem 2

OpenStudy (campbell_st):

the new question uses the property the square of the length of a tangent from an external point is equal to the product of the intercepts of the secant AC is a secant AI is a tangent then AF*AC = AI ^2 and AD is a secant from the same point so AE*AD = AI^2 then AF*AC=AD*AE the missing infromation is AE

OpenStudy (anonymous):

Campbell, can you perhaps scroll up and explain the first problem? we never figured it out

OpenStudy (anonymous):

And @thechocoluver445 I have one more problem for you. Then, I'm done. :)

OpenStudy (anonymous):

Ok:)

OpenStudy (campbell_st):

I've looked at it... the diagram made it a bit difficult |dw:1339706676837:dw|

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