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Mathematics 13 Online
OpenStudy (anonymous):

Solve. 3x2 = –21x – 15

OpenStudy (anonymous):

Using quadratic formula

OpenStudy (anonymous):

3x^2+21x+15 a=3, b=21, c=15 -b±√b^2-4ac/2a plug in and solve.

OpenStudy (anonymous):

OK.

OpenStudy (anonymous):

I don't know whtat the b^2 - 4(a)(c) is

OpenStudy (anonymous):

-b±√b^2-4ac/2a is the quadratic formula.

OpenStudy (anonymous):

Yeah, I know but I don't know what the answer is for b^2 - 4(a)(c)

OpenStudy (anonymous):

lets plug in, a, b and c. -(21)±√21^2-4(3)(15)/2(3)

OpenStudy (anonymous):

I got 126 inside the radical

OpenStudy (anonymous):

261*

OpenStudy (anonymous):

You are correct.

OpenStudy (anonymous):

Okay, then what do I do?

OpenStudy (anonymous):

This website should give you some clarification on solving the quadratic formula. http://www.purplemath.com/modules/quadform.htm

OpenStudy (anonymous):

Thanks.

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