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Solve. 3x2 = –21x – 15
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Using quadratic formula
3x^2+21x+15 a=3, b=21, c=15 -b±√b^2-4ac/2a plug in and solve.
OK.
I don't know whtat the b^2 - 4(a)(c) is
-b±√b^2-4ac/2a is the quadratic formula.
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Yeah, I know but I don't know what the answer is for b^2 - 4(a)(c)
lets plug in, a, b and c. -(21)±√21^2-4(3)(15)/2(3)
I got 126 inside the radical
261*
You are correct.
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Okay, then what do I do?
This website should give you some clarification on solving the quadratic formula. http://www.purplemath.com/modules/quadform.htm
Thanks.
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