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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros. 1) -2, -1, 1 2) i, 4 3) i, 2 - √3 4) 1, 4, 1 + √2
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Hint: \((x-a)(x-b)(x-c)\) will have zeroes a, b, and c.
I am really confused lol
In other words, if you have zeroes a, b, and c, a polynomial that would have those zeroes would be \((x-a)(x-b)(x-c)\).
So for 1 it would be like (x-2)(x-1)(x-1) I'm sorry I'm not good at math at all
You have the right idea...just be careful with your signs.
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So did I do the first one right? lol
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