The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. How much space is between the ball and the rim if someone makes a shot and the ball goes exactly through the center of the rim?
how much space means you need to fnd the volume so find the volume of a basketball with the 18-inch diameter and the volume of a standard basketball...then subtract them do you need more help?@jayda
@jayda
so what would the diameter of the standard basketball be
circumference = \(\pi d\) diameter = \(\frac{circumference}{\pi}\)
so divide 30 by pi to get the diameter
so 9.6.
yup that's the diameter
and is the formula 4/3 x pi x r squared?
r cube \[\large V = \frac{4}{3} \pi r^3\]
woops yeah i meant cubed
so can you solve the two volumes now?
yeah
great! so to summarize.... it's \[\huge V_{\text{rim}} - V_{\text{basketball}} = \text{answer}\]
V means volume ;)
652?
hmm let me check..
i dont think its right. its none of my answers. ha
\[V_{rim} = \frac{4}{3} \pi (9)^3\] \[V_{rim} = 3054\] \[V_{ball} = \frac{4}{3} \pi (4.8)^3\] \[V_{ball} = 463\] were those what you got?
no i didnt get them.. but i tried it again and i got them. idk why i didnt get them the first time? ha
hmm maybe you didnt divide by 2 to get the radius?
im not sure. so then subtract 3054 and 463?
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