Question

show solution please...
@lgbasallote ,
\[\large \int_{0}^{s}axdx= \]

Answer 1

a is a constant...

Answer 2

as^2 /2 ?

Answer 3

how?

Answer 4

\[\large \int_{0}^{s}axdx=[\frac{ax^2}{2}]^{s} _{0} =\frac{as^2}{2}\]

Answer 5

\[\int\limits_0^s ax\cdot\text dx=\left.\frac{ax^2}{2}\right|_0^s=\frac{as^2}{2}\]

Answer 6

ok... that makes sense...

Answer 7

yes?

Answer 8

perfect.. thank you...:)

Answer 9

too easy

Answer 10

Not easy for me..

Answer 11

me neither.... someone told me this was a special integral... can't remember though...

Answer 12

a is a constant => take it out of the integral
=> \(\large a \int_{0}^{s}xdx\)
Then, it looks good :)

Answer 13

so you can pull any constant out of the integral sign , right?

Answer 14

yes you can factor a constant out of the integral

Answer 15

Hmm.. Sorry, I should make it clear..
The coefficient of variable.
Constant is like +C => not pull out..

Answer 16

so why was this supposed to be some special integral? idk....

Answer 17

Perhaps, it's special when you have to apply it? I don't know too, sorry!

Answer 18

\[\int\limits_a^b (x+a)\cdot\text dx=\int\limits_a^b x\cdot \text dx+a\int\limits_a^b \text dx=\left.\left(\frac{x^2}{2}+ax\right)\right|_a^b\]

Answer 19

@lgbasallote ,??

Answer 20

Oh.. that a is a constant!!

Answer 21

@dpaInc asked a question! :O
Am i dreaming?

Answer 22

@saifoo.khan You're not

Answer 23

Pinch me!

Answer 24

\[\huge \frac{as^2}{2} = \frac{a*s*s}{2}\]

Answer 25

:O, half-a** integral...

Answer 26

another fun integral

\[\huge \int e^{1+ \ln x}dx\] try it :)

Answer 27

tough one...

Answer 28

\[\int e^{1+ \ln x}dx = \int e(e^{\ln x})dx = \int exdx = e\int xdx = ...\]

Answer 29

why can you pull the e out?

Answer 30

because e is a constant, and its value is 2.718