Question

log x √x^2+1

i have to write as a sum, i don't know where to start

Answer 1

this is what it looks like \[\log x \sqrt{x^{2}+1}\]

Answer 2

log(ab) = log(a) + log(b)

can you start now ?

Answer 3

so it
s be log x + log √x^2+1?

Answer 4

thats not complete yet. you can expand second term further.

\[\log m ^{n} = n \log m\]

Answer 5

Hints:
\(\Large \log(\color{red}a \color{blue}b) = \log (\color{red} a ) +\log( \color{blue} b)\)
\(\Large \log( a^{\color{green} n})= \color{green} n \log (a)\)

Answer 6

so \[\log x +{1/2}\log x^2 +1\]

Answer 7

Don't forget your parenthesis...it's incorrect otherwise.\[\log x + \frac 12 \log\color{red}( x^2 +1\color{red})\]