Question

-3^-2

Answer 1

\[-3^{-2}=-\frac{1}{3^2}\]

Answer 2

\[(-3)^{-2}=\frac{1}{(-3)^2}=\frac{1}{3^2}\]

Answer 3

thanks, what about -3^0

Answer 4

\[-3^0=-1\]
but
\[(-3)^0=1\]

Answer 5

so its a trick question? there are no parenthesis

Answer 6

do you think the - is ment to squared too?

Answer 7

the actual question was solve for x= -3
x^-2
x^-1
x^0
x^1
x^2
i solved t he x^1 and x^2 myself

Answer 8

well all of x is being squared so the negative would get squared ...etc

Answer 9

when \[x=-3\]\[x^{-2}=(-3)^{-2}=\frac{1}{(-3)^2}\]

Answer 10

i hope you squared away the negative in x^2 when x=-3

Answer 11

yes, -3^2=9

Answer 12

yeah but to avoid confusion
is is better to write
(-3)^2=9

Answer 13

ok, thanks

Answer 14

\[\Huge{\color{red}{-3x^{-2}}}\]\[\LARGE{\color{green}{\implies \frac{1}{-3^2}^2}}\]\[\LARGE{\color{blue}{\implies x=\frac{1}{9}}}\]