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Mathematics 13 Online
OpenStudy (anonymous):

Find the lateral area for the prism

OpenStudy (anonymous):

This is easy now that we have done total area. Lateral Area is just total area without the sides, i.e. ph.

OpenStudy (anonymous):

OpenStudy (anonymous):

its a different problem

OpenStudy (anonymous):

Okay, so you need p this time. How would you find the hypotenuse of the triangle? Do you know pythagoras' theorem?

OpenStudy (anonymous):

yes, \[a^2 + b^2= c^2\]

OpenStudy (anonymous):

Okay, so what's the hypotenuse of the triangle in this case?

OpenStudy (anonymous):

hold on let me work it out real fast!

OpenStudy (anonymous):

Okay.

OpenStudy (anonymous):

7.21 for C it would be 4^2+6^2=c^2 right?

OpenStudy (anonymous):

yep. But they want you to keep it in exact form, so keep it as a square root.

OpenStudy (anonymous):

What is the perimeter then?

OpenStudy (anonymous):

No, not quite. The perimeter of the triangle would be the sum of all the sides of the triangle.

OpenStudy (anonymous):

And you'll want to keep the \[\sqrt{52}\] as it is.

OpenStudy (anonymous):

okayy!! so the would the perimeter be 20??

OpenStudy (anonymous):

Hm. No. 4 + 6 + sqrt(52)

OpenStudy (anonymous):

that's the perimeter of the triangle at the top, which you're trying to find.

OpenStudy (anonymous):

oh okay!!

OpenStudy (anonymous):

And then what should you do next to get the lateral area?

OpenStudy (anonymous):

times it by 8 because its perimeter times height and 8 is the height

OpenStudy (anonymous):

Yupp. Well done :)

OpenStudy (anonymous):

You're still not done though, what's your answer now?

OpenStudy (anonymous):

10+80= sq. root of 52 (thats the form its wants in the book for the answer)

OpenStudy (anonymous):

Hm. Not quite. Okay. ( 10 + sqrt(52) ) * 8 = 80 + 8 sqrt(52). That's the lateral area. Do you see why?

OpenStudy (anonymous):

But you still have to simplify sqrt(52). Do you know how?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay. Good, you should have your answer then :)

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