Find the lateral area for the prism
This is easy now that we have done total area. Lateral Area is just total area without the sides, i.e. ph.
its a different problem
Okay, so you need p this time. How would you find the hypotenuse of the triangle? Do you know pythagoras' theorem?
yes, \[a^2 + b^2= c^2\]
Okay, so what's the hypotenuse of the triangle in this case?
hold on let me work it out real fast!
Okay.
7.21 for C it would be 4^2+6^2=c^2 right?
yep. But they want you to keep it in exact form, so keep it as a square root.
What is the perimeter then?
No, not quite. The perimeter of the triangle would be the sum of all the sides of the triangle.
And you'll want to keep the \[\sqrt{52}\] as it is.
okayy!! so the would the perimeter be 20??
Hm. No. 4 + 6 + sqrt(52)
that's the perimeter of the triangle at the top, which you're trying to find.
oh okay!!
And then what should you do next to get the lateral area?
times it by 8 because its perimeter times height and 8 is the height
Yupp. Well done :)
You're still not done though, what's your answer now?
10+80= sq. root of 52 (thats the form its wants in the book for the answer)
Hm. Not quite. Okay. ( 10 + sqrt(52) ) * 8 = 80 + 8 sqrt(52). That's the lateral area. Do you see why?
But you still have to simplify sqrt(52). Do you know how?
yes
Okay. Good, you should have your answer then :)
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