Question

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Step by Step Please

Answer 1

\[\frac{3}{10} (t+2)-\frac{t}{20}\ge\frac 35\]
Do you know the LCM of 5, 10 and 20?

Answer 2

20

Answer 3

Good, so multiply the whole equation by 20

Answer 4

And post what do you get?

Answer 5

120t -t+240 greater than or egual to 12
This is where i am now

Answer 6

uh-huh you made a little mistake,
\[20 \times \frac{3}{10} (t+2)-20 \times\frac{t}{20}\ge20 \times\frac 35\]
\[\cancel{20}2 \times \frac{3}{\cancel{10}} (t+2)-\cancel{20} \times\frac{t}{\cancel{20}}\ge\cancel{20}4 \times\frac 3{\cancel{5}}\]
so we get
\[2\times 3(t+2)-t\ge 4\times 3\]
Do you get this?

Answer 7

Oh.. I do now. i seperated the 3/10 from t+2 in the beginning

Answer 8

Now simplify, and post what you get?

Answer 9

T is greater than or equal to 0!?

Answer 10

Yeah:D You are right:)

Answer 11

Did you understand?

Answer 12

Yayyyy! Thanks Ash! And thanks for the medal :) And yes i did I made a silly mistake.

Answer 13

You're welcome:D