The value of C (12, 10) is?
\( \color{Black}{\Rightarrow C(n,r) = \large{n! \over (n -r)!r!} }\)
\( \color{Black}{\Rightarrow C(12,10) = {12! \over (12 -10)!10!} }\)
another way of evaluating this is by noting that C(12,10) = C(12.2) and you write C(12,10) = 12*11 ---- 2*1 this follows from the rule quoted by ParthKohli
^ Where is the LaTeX lol
Thanks guys!
yea - i know - thanx for the tuition - i'll have to practice it - but i'm too tired now its late here in uk and i'm about to turn in
lol xP
Wait, for cwrw's method I got 66. But for parth I got 66...
*132
There's certainly a mistake you've done :/
So the answer is 66?
The formula that I said leads to cwrw's statement. It's 66 in both. =))
Oh woops, I calculated yours wrong :/ Thanks for the clear up.
Ah it's all good dw we all have our times :P
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