Question

another question from my algebra book ;)

an openstudy user gets his first fan 4 months after he joined. he gets to 100 fans 2 months after this. then he gets to 200 fans 19 days after. He gets to 300 fans 15 days after. Then he gets to 400 fans 29 days after. He reaches 500 fans 20 days after.

create a function/equation representing his progress

Answer 1

lol

Answer 2

that's you ;p

Answer 3

lol you're fast

Answer 4

you came here before i did

Answer 5

There's no function I see here

Answer 6

then how can i represent this?

Answer 7

and no this aint me..im not 500 fans :p

Answer 8

Though, f(1) = 120
f(100) = 180
f(200) = 199
f(300) = 214
f(400) = 243
f(500) = 263
You can create an array function

Answer 9

i see

Answer 10

f(x) = {120 if x = 1
{180 if x = 100

etc.

Answer 11

There's no common thing I see between them lol

Answer 12

And good job, you've kept the records xD

Answer 13

this is an even-number in my book so it doesnt give answers :/

Answer 14

So is it really about OpenStudy or you modified it a bit?

Answer 15

openstudy..i wrote it remember :p

Answer 16

so summary...a progress has to be consistent for it to be function-ed?

Answer 17

How does your book know about OS? o.o

Answer 18

Yeah, it has to have something in common.

Answer 19

i wrote it :p

Answer 20

This, my dear sir, is completely random :P

Answer 21

*my* book

Answer 22

making any sense?

Answer 23

oh lol

Answer 24

YOUR book xP

Answer 25

lol

Answer 26

functions have infinite number of notations, but this array thing is the one I'm telling you

Answer 27

Yours might be different tho

Answer 28

How do you make a { in latex?

Answer 29

dunno

Answer 30

Oh yeah, Sat knows. Let me go to the \(\LaTeX\) group.

Answer 31

\[\huge \text{{}}\]

Answer 32

\( \color{Black}{\Rightarrow \Large\left\{ \begin{matrix}f(x) = x^2 - 1 \\ f(x) = x^2 + 1 \end{matrix}\right.}\)

Answer 33

Yeah it was easy

Answer 34

dont spam my post lol