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Find the zeros of the polynomial function and state the multiplicity of each. 4(x + 4)3(x - 4)(x - 2 + i)
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So, to find the zeroes, we set the expression equal to zero and solve for the x's: 4(x + 4)^3 (x - 4) (x - 2 + i) = 0 (x + 4)^3 (x - 4) (x - 2 + i) = 0 To get 0, the individual factors must equal 0. So, we solve for x in these cases: x + 4 = 0 x - 4 = 0 x - 2 + i = 0 The multiplicity is just how many times the factor occurs in the polynomial. E.g., the first is cubed so it occurs three times, therefore the multiplicity is 3 of that root.
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