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suppose that $2300 in initially invested in an account at a fixed interest rate, compounded continuously. After 3 years, the amount of money in the account is $2672. Find the interest rate per year. The answer should be written as a percentage. please and thank you!!
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\[M = P e ^{r.t}\]
\[2672 = 2300 e ^{r . 3}\]
oh okay, then what do i do??
divide both sides by 2300
okay then?
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\[2672/2300 = e ^{3r}\]
take natural log both sides
\[\ln (2672/2300) =3r\]
r = 5 %
thats per year??
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correct.. r = 3 years right... so its 5 % per year
oh okay thank you so muchhh!
spend some time on "e" in your free time.. its an amazing number
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