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How do you factor..?
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\[x ^{2}-6x+9-4y ^{2}\]
Is it equal to zero?
@sakigirl could u check your question again
okay i will tell ya how u do it
Oh okay, thanks @razor99
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There a perfect square right there.
\(x^2-6x+9=(x-3)^2\)
x^2-6x+9-4y^2 x.x-2.3.x+3.3-2.2.y.y
so u know the common factor
Is it a 1+3 type?
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Then \(4y^2=(2y)^2\)
Factored form: \((x-3)^2-(2y)^2\)
@razor99 that looks like \[2.2\] as opposed to \[2 \times 2\]
oh srry guyz its not a dot
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