Question

7^(x + 1) = 2^3x. Solve for x.

Answer 1

\[\huge{7^{x+1}=2^3 x}\]
\[\huge{\frac{7^{x+1}}{2^3}=x}\]
\[\huge{\frac{7^{x+1}}{8}=x}\]

Answer 2

I'm sure the OP meant 2 to the 3X power

Answer 3

yeah, sorry, 2^(3x)

Answer 4

\[7^{(x + 1)} = 2^{3x} \]\[(x+1)log7 = 3xlog2\]\[log7 = 3xlog2-xlog7\]\[log7 = x(3log2-log7)\]\[ x = \frac{log7}{(3log2-log7)}\]

Answer 5

I'm trying to wrap my head around that.

Answer 6

I don't get the third step, log7=3xlog2−xlog7.

Answer 7

How did you go from the second step to the third?

Answer 8

That was correct, thanks!

Answer 9

Sorry, I skipped a step there..
(x+1)log7=3xlog2
xlog7 + log7 = 3xlog2
log7=3xlog2−xlog7.

Answer 10

Callisto distributed log7 to stuffs in parentheses