hi help in basic arithmetic algebra

Question

mathslover · Answer

attachment

lgbasallote · Answer

lol nice intro ;)

mathslover · Answer

:).... can u help @lgbasallote

anonymous · Answer

You need to post your question in order for people to answer it.

mathslover · Answer

i had posted the image @Wired  ... see it

lgbasallote · Answer

@mathslover

kinggeorge · Answer

How far have you gotten on your own?

mathslover · Answer

nice reply @lgbasallote  .....this means that you can not help me ....

anonymous · Answer

cual es la pregunta ¿

lgbasallote · Answer

yeah.. im not knowledgeable in basic arithmetic algebra :(

anonymous · Answer

The image just popped up.

mathslover · Answer

i think this can be proved like this :

If x  > 1 then we can say that 1.x > 1 ... So n = 1 and i think it is done 

but i think this is not a proper way

mathslover · Answer

@KingGeorge  ...

kinggeorge · Answer

That proves it if $x\ge1$. We also need to consider the case where $0<x<1$.

mathslover · Answer

we can apply the archimedean property to number 1/x ...

kinggeorge · Answer

By definition, there exists some $x^{-1}>0$ (i.e $\frac{1}{x}$) such that $$x\cdot x^{-1}=1$$Now, take $n\in\mathbb{N}$ such that $n>x^{-1}$. This means that $$x\cdot n>x\cdot x^{-1}=1$$Thus, $x\cdot n>1$.

mathslover · Answer

ok thanks a lot...

kinggeorge · Answer

You're welcome.