Question

some body help me plzzzz
solve

Answer 1

\[3+\sqrt{z-6}=\sqrt{2-9}\]

Answer 2

just checking, is the 2 on the RHS of the equation supposed to be a z?

Answer 3

well..you familiar with complex nos then madam ?

Answer 4

@ebbflo srry i wz wrong

Answer 5

yes it is Z

Answer 6

\[3+\sqrt{z-6}=\sqrt{z+9}\]

Answer 7

this the right question

Answer 8

ok
\[3+\sqrt{z-6}=\sqrt{z+9}\]
\[(3+\sqrt{z-6})^2=(\sqrt{z+9})^2\]
\[9+6\sqrt{z-6}+z-6=z+9\]
\[6\sqrt{z-6}=6\]
\[\sqrt{z-6}=1\]
\[z-6=1\]
\[z=7\]

Answer 9

z=7

Answer 10

err, i made a mistake, one sec, tried to save all the code I wrote for the first eq...

Answer 11

no take it back, its good

Answer 12

yep..pretty good :)

Answer 13

u cool thanks a lot :D