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F= {(x,y):y=x^2} What is the domain and range of F?
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The domain of F is all possible x-values, and in this case, you can input virtually any real number into this function, so its domain is R, all real numbers. The range of F is all possible y-values, given that you'll only take x-values from the domain. Think about it, can you possibly get negative values for y? You cannot, any output from f(x) = x^2 will always be non-negative, so the range of this function is: All real numbers from 0 to infinity, or in interval notation: [0, infinity) (note the square bracket by the 0, indicating that 0 is part of the set) Hope that helps :)
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