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Find the axis symmetry of the parabola formed by the following quadratic function: y=3x^2+7x-4 a.)x=7/3 b.)-7/3 c.)x=7/6 d.)-7/6
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hey this almost the same one!
remember the vertex was right in the middle?
well so is the axis of symmetry
y=ax^2 +bx +c y=3x^2+7x-4
a = ??
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2
no no! remember from the last one. What number is in the place of a?
y=ax^2 +bx +c y=3x^2+7x-4
3
yes! a = 3
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b =??
b=7?
yep!
a= 3 b=7
so its a?
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nope
heres your graph:
|dw:1340041230348:dw|
they want this line|dw:1340041257172:dw|
but the cool thig is it passes throught the vertex just like the last one
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|dw:1340041290116:dw|
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