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Mathematics 7 Online
OpenStudy (anonymous):

Find the axis symmetry of the parabola formed by the following quadratic function: y=3x^2+7x-4 a.)x=7/3 b.)-7/3 c.)x=7/6 d.)-7/6

OpenStudy (eyust707):

hey this almost the same one!

OpenStudy (eyust707):

remember the vertex was right in the middle?

OpenStudy (eyust707):

well so is the axis of symmetry

OpenStudy (eyust707):

y=ax^2 +bx +c y=3x^2+7x-4

OpenStudy (eyust707):

a = ??

OpenStudy (anonymous):

2

OpenStudy (eyust707):

no no! remember from the last one. What number is in the place of a?

OpenStudy (eyust707):

y=ax^2 +bx +c y=3x^2+7x-4

OpenStudy (anonymous):

3

OpenStudy (eyust707):

yes! a = 3

OpenStudy (eyust707):

b =??

OpenStudy (anonymous):

b=7?

OpenStudy (eyust707):

yep!

OpenStudy (eyust707):

a= 3 b=7

OpenStudy (anonymous):

so its a?

OpenStudy (eyust707):

nope

OpenStudy (eyust707):

heres your graph:

OpenStudy (eyust707):

|dw:1340041230348:dw|

OpenStudy (eyust707):

they want this line|dw:1340041257172:dw|

OpenStudy (eyust707):

but the cool thig is it passes throught the vertex just like the last one

OpenStudy (eyust707):

|dw:1340041290116:dw|

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