Question

\[\huge \int\limits \frac {e^{8/x}}{x^2} dx\] = ? + C
(looking mainly for help with setup with tips & tricks; will give a medal :-) )

Answer 1

Put
\[u=\frac 8 x
\]

Answer 2

\[
du = -\frac 8 {x^2} dx
\]

Answer 3

\[
\int \frac{e^{8/x}}{x^2} \, dx= -\frac 1 8 \int e^u du=-\frac 1 8 e^u + C
\]

Answer 4

\[
\int \frac{e^{8/x}}{x^2} \,
dx=-\frac{e^{8/x}}{8} + C
\]

Answer 5

Ah so a simple u substitution was thrown in there with the others... >_< Doh! Well ty for the help

Answer 6

yw