Question

Solve 5^3x + 1 = 25x + 1
a.x = 4
b.x = -2
c.x = 1
d.x = 0

Answer 1

first move all your "X"'s to one side and all your integers to another:
\[5^3x-25x=-1+1\]

Now simply solve for "X"
5^3x-25x=0
now no matter what you do to the other side, you will still have "0"

There-fore, your answer is 0

Answer 2

hard to work out the equation

\[5^{3x} + 1= 25^x + 1\]

but if it is.. here's a solution

write the rhs in terms of 5 to a power

\[5^{3x} + 1 = (5^2)^x + 1\]

this gives

\[5^{3x} + 1 = 5^{2x} +1\]

subtract 1 from both sides

\[5^{3x} = 5^{2x} \]

since the bases are the same equate the powers

3x = 2x

solve for x

Answer 3

^ DOH! forgot all about that lol

Answer 4

hope it helped