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Mathematics 15 Online
OpenStudy (anonymous):

W

OpenStudy (anonymous):

Surface area is basically the area of all the sides...You agree that the front side facing us will have the same area of the back side facing away from us? So you find this area call it F (for front) So F=Triangular area + rectangular lower area and you'll have twice this right? so you have 2F Then you have to find the area of one of the sides (both of the sides have the same area, we are assuming this tent is symmetric)...Call this area S, so your S=7ft*3ft =21 square feet and you have twice this so you have 2S Now you have to finally include the area of the top of the tent call it T for top T=7feet* 5 feet=35 square feet and you have twice this so you have 2T So your TOTAL SURFACE AREA=2F+2S+2T

OpenStudy (anonymous):

187

OpenStudy (anonymous):

Notice we found S and T very easily, the part we need to calculate is F F=Triangular area + rectangular lower area F= ( ) + (6 feet* 3 feet)= ( ) + 18 feet square Find what goes in the parenthesis... You can break it up into the two right triangles (A right triangle has a 90 degree angle)

OpenStudy (anonymous):

145in2

OpenStudy (anonymous):

This forum isn't just to give answers out it is to have explanations and the person who asks to understand if you simply want answers you won't learn you will simply use openstudy to cheat

OpenStudy (anonymous):

PLZ DON'T JUST GIVE ANSWERS

OpenStudy (anonymous):

oh im sorry.

OpenStudy (anonymous):

Exactly "&" is the key here not just simply answers alone. Have a nice day.

OpenStudy (anonymous):

omg what a bummer!

OpenStudy (anonymous):

lol :) okay

OpenStudy (anonymous):

No I'm part of a team that manages the forum so that students are not encouraged to join for the wrong purposes...I was simply reminding the users of this thread that answers should accompany an explanation for it...otherwise students compare their answers with others and clearly specify "I got (blank) can you tell me what you have?" ...anyhow did you want any further explanation in any of the exercises you presented. I'm always more than happy to help and encourage :-)

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