Question

How do I factor this polynomial?

Answer 1

\[x ^{2}-6x+9-4y ^{y}\]

Answer 2

that's not a polynomal... that last term is \[\huge 4y^y \]

Answer 3

Oops, it has to be squared. I'm sorry.

Answer 4

:)

Answer 5

Can you help?

Answer 6

i'm trying...:)

Answer 7

ok... so this is your POLYNOMIAL:
\[\huge x^2-6x+9-4y^2 \]
correct?

Answer 8

Yes. :)

Answer 9

can you factor just this part: \(\large x^2-6x+9= \)

Answer 10

And then what do I do with the 4y^12?

Answer 11

did you factor it?

Answer 12

do you need help?

Answer 13

(x-3)(x-3)

Answer 14

good notice it is a perfect square... so your problem can be written as:

Answer 15

\[\huge x^2-6x+9-4y^2 \]
=\[\huge (x-3)^2-4y^2 \]
=\[\huge (x-3)^2-(2y)^2 \]

now we have a difference of squares...
do you know how to factor \(\large a^2-b^2= \)

Answer 16

No, can you show me?