Question

(4x^3 - 4x^2 - 9x + 9) ÷ (x + 3)

help plz?

Answer 1

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x+3 | 4x^4-4x^2-9x+9

how many times does x go into 4x^4?

Answer 2

uh? I think 4.

Answer 3

what about the x part
how many times does x go into x^4?

Answer 4

\[\frac{x^4}{x}=\frac{x \cdot x \cdot x \cdot x}{x}\]

Answer 5

does anything cancel?

Answer 6

those x's?? im kinda confused.

Answer 7

right side?

Answer 8

yes those are x's

Answer 9

@myininaya, you added an x when you copied the equation. It's \[4x^{3}\]not\[4x^{4}\]

Answer 10

is -108 the remainder???

Answer 11

oh okay how many times does
x go into 4x^3?

\[\frac{4x^3}{x}=\frac{4 \cdot x \cdot x \cdot x}{x}\]
what cancels @j3rseykid1 ?

Answer 12

There is also synthetic division if long division for this one

Answer 13

Have you learned synthetic division?

Answer 14

a little. im still learning it.

Answer 15

Do you know how to set it up?

Answer 16

yes

Answer 17

Is that how you would set it up:

-3 | 4 -4 -9 9
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We didn't need any zero placeholders because the exponents didn't skip any integers
what i mean is we have 3,2,1,0
No integers skipped

Answer 18

yes, i set it up like that.

Answer 19

great do you know the next step?

Answer 20

i think you would bring the 3 down and do

Answer 21

what 3
there is no 3 there
you mean 4?
if so that is correct

Answer 22

oh yes i ment 4..lol.

Answer 23

Make sure you are using the correct equation! @j3rseykid1 said 4x^3, but @myininaya said 4x^4 in her first post. Don't solve for the wrong equation!

Answer 24

I guess ima throw in the white flag on this one...#CLOSE

Answer 25

yes you bring down the 4

Answer 26

-3 | 4 -4 -9 9
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4 |

Next step is?