Question

4x=square root 8+8x

Answer 1

\[\huge{4x=\sqrt{8+8x}}\]
\[\huge{16x^2=8+8x}\]
\[\huge{16x^2-8x-8=0}\]
\[\huge{a = 16 , b = -8,c =- 8 }\] can u solve it now ?

Answer 2

No..

Answer 3

with the help of quadratic equation :
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 4

with the help of this formula?

Answer 5

try to solve ..

Answer 6

\[4x = \sqrt{8+8x}\]

\[=> 16x^2 = 8+8x\]
\[=> 2x^2 - x - 1 = 0\]
\[=> 2x^2 - 2x + x - 1 = 0\]
\[=> 2x(x - 1)+1(x-1) = 0\]
\[=> (2x+1)(x-1) = 0\]
\[=> x = \frac{-1}{2} or (1)\]

Answer 7

I honestly don't know how.

Answer 8

@mathslover I don't think there is any need for applying quadratic formula

Answer 9

I agree, you don't need to apply the quadratic formula here. You can if you want to, but unless you're a computer program there's methods that take less time.