A boat makes a 120-mile trip downstream in 3 hours but makes the return trip in 4 hours. What is the rate of the current? answer list 3 mph 4 mph 5 mph
do u know how to do this
using algebra Let ‘c’ be the rate of current, and ‘b’ be the rate of boat with no current...
ok
remember, distance = rate \(\times\) time \(\large D=r \cdot t\) .... or \[\implies \Large \frac D r = t\]
40
so, you get 2 equations: \[\Large {120 \over 3} = b+c\] \[\Large {120 \over 4} = b-c\] solve for c
how do i do that
have you used simultaneous equations before?
did you understand how to get the two equations above?
1 one is 40b+c an the 2 one is 30=b-c an no
yea, so to get ‘c’, we subtract the second equation from the first
how does this look like
\[\large 40 = b+c\]\[\large 30 = b-c\]- - +\[\large \overline{10 = 0+2c}\]
5=c
\[\Huge \checkmark\]
yes thx alot
if you wanted to know the speed of the boat b: plug in 5 for c in any 1 of the 2 equations ...........you get 35
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