Question

Quadratic Functions, Question is attached

Answer 1

Find the vertex.

Answer 2

So i'd type it into a graphing calculator?

Answer 3

x coordinate is -b/2a.

Answer 4

The maximum value is y-value of the vertex. Your book should have the cheat for that.

Answer 5

Find that and then plug it in to find the y value of the vertex. That will be the maximum.

Answer 6

Don't have a book :/ summer school.

Answer 7

online*

Answer 8

B is the value next to the x, right?

Answer 9

the vertex of the equation
\[f(x)=ax^{2}+bx+c\] is the point (-b/2a, f(-b/2a)). In other words, find the x-value (x = -b/2a) and plug that into the function to find the y-value.

Answer 10

So the x value is 1, right?

Answer 11

I don't get what to do after that.

Answer 12

Now plug that value in for x in your equation. The answer is the y-value, which is the min/max (in this case a max).

Answer 13

Oh, it's 6?

Answer 14

yes.
Find that and then plug it in to find the y value of the vertex. That will be the maximum.