Quadratic Functions, Question is attached

Question

anonymous · Answer

attachment

mertsj · Answer

Find the vertex.

anonymous · Answer

So i'd type it into a graphing calculator?

mertsj · Answer

x coordinate is -b/2a.

anonymous · Answer

The maximum value is y-value of the vertex.  Your book should have the cheat for that.

mertsj · Answer

Find that and then plug it in to find the y value of the vertex.  That will be the maximum.

anonymous · Answer

Don't have a book :/ summer school.

anonymous · Answer

online*

anonymous · Answer

B is the value next to the x, right?

anonymous · Answer

the vertex of the equation
$$f(x)=ax^{2}+bx+c$$ is the point (-b/2a, f(-b/2a)).  In other words, find the x-value (x = -b/2a) and plug that into the function to find the y-value.

mertsj · Answer

|dw:1340232041892:dw|

anonymous · Answer

So the x value is 1, right?

anonymous · Answer

I don't get what to do after that.

anonymous · Answer

Now plug that value in for x in your equation.  The answer is the y-value, which is the min/max (in this case a max).

anonymous · Answer

Oh, it's 6?

mertsj · Answer

yes.  
Find that and then plug it in to find the y value of the vertex.  That will be the maximum.