Quadratic Functions - question is attached

Question

anonymous · Answer

attachment

anonymous · Answer

Expand.  The quadratic term is the one with the square, the linear has only an x, and the constant has no variable.

cwrw238 · Answer

hint - term  5x^2 is eliminated  when you expand

anonymous · Answer

How do I expand? Multiply everything?

anonymous · Answer

Distributive property.  Some people use the dirty 4-letter F-word...FOIL.

anonymous · Answer

Ok so I got -21x-20. There're only two terms.. is one of them the -5x^2?

cwrw238 · Answer

expand (x - 5)(5x + 4)
multiply the second bracket by x then  multiply it by - 5

cwrw238 · Answer

no 5x^2 is eliminated

anonymous · Answer

if you only have 2 terms, what's the coefficient of the quadratic term?

anonymous · Answer

I have no idea. is it 1?

anonymous · Answer

And how do I know what type of problem it is?

anonymous · Answer

If it's not there, the coefficient is 0.

anonymous · Answer

oh. so it would be choice b?

anonymous · Answer

If there is no quadratic term, then move to the next power...linear.

anonymous · Answer

Sorry, I don't usually provide direct answers here.  Just helpful questions.

anonymous · Answer

alright well b is the only one that seems to make sense, thanks

cwrw238 · Answer

a quadratic function contains a term in x^2

anonymous · Answer

Alright, thanks a lot

cwrw238 · Answer

yw -  its either b or d - have a good look