Find the coordinates for the center and length of radius for this circle. (x + 3)2 + (y - 5)2 = 25 center (,) radius
What is the equation for a circle?
(x-h squared) + (y-k squared) = r squared
right. How can you make a plus out of minuses (Hint: x+3 needs to look like x - something)
x - 6
no i have to square 3 so it should be 9
Remember that you need the 3 in there somewhere. x+3 is the same as x - (-3) isn't it?
thats correct
DO NOT EXPAND!!!! The answer is in front of you.
is it 9 and 25 and radius 5
the center is 9 and 25 radius 5
The radius is 5...But you have to find h and k to find the center. That means that you need to make (x+3) look like (x - (-3)). What's h? Then, look at (y-5). Does is look like (y-k)? If so, what's k?
The center is at (h, k)
-3
what's k?
-5
Look at the structure:\[(x-h)^{2} +(y-k)^{2}=r^{2}\]
The minus sign MUST be there. What's k?
-5
so basically its the same numbers but you have to make them negative
Sorry. Just 5. No negative. We needed a negative on the 3 for x because there was a plus sign in between, and we needed a minus sign.
Center at (h, k) = (-3, 5)
When working with these types of equations, the structure (signs, powers, placement) is the important thing.
okay can you help with the next one to see if i understand
Find the coordinates for the center and length of radius for this circle. (x - 3)2 + (y - 5)2 = 8 center (,) radius
so the answer would be 3, 5 and 2 square root of 2
right
i am not sure about 2 square root of 2 because it should equally 8
okay thanks
this is alot easier than i thought it would be
But remember that the radius is the square root of what's on the right. Simplifying that is what gave you the 2root 2
Yeah, it's not bad.
Find the coordinates for the center and length of radius for this circle. (x - 4)2 + y2 = 12 on this one what do i do with the y squared would it be -1
There is no k, so k=0
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