Please help!! Find the nth partial sum of the arithmetic sequence: 1.50, 1.45, 1.40, 1.35 . . . n=20
I think it is 0.55, is that correct?
not sure what you mean by nth partial sum
It just means add up the first n terms. In this case, n = 20, so add up the first 20 terms.
ok Is 0.55 correct, can you just tell me?
no, you have 20 terms which most are over 0.55, so it's definitely not possible to add positive numbers over 0.55 to get 0.55
sum of 20 terms = 10(2*1.5 + (20-1)*-0.5)
can you show me what to do? and how to get the answer?
* 10(2*1.5 + 19*-0.05) difference -0.05 not -0.5
Sum of first n terms = (number of terms)*(first term+nth term)/2
So S = (n*(a1 + an))/2
r=1.45-1.50=-0.05 \[u _{1}=1.50\rightarrow u _{n}=1.55-n0.05\]\[\sum_{n=1}^{20}u _{n}=20\times1.55-0.05\times20\times21\div2=20.5\]Or your question is\[u _{20}=20\times(-0.05)+1.55=1.55-1=0.55\]
formula for sum n terms = (n/2)(2a + (n-1)d)
So my answer, 0.55, is right then syderitic?
@cwrw238 is that right?
no, the answer isn't 0.55
then idk what is?
look, if you want the sum of the first 20 terms, then the answer is 20.5 if you want the 20th term of that sequence then the answer is 0.55
Plug n = 20, a1 = 1.5 and an = 0.55 into S = (n*(a1 + an))/2 to find the sum
it says Find the nth partial sum @Syderitic
So @jim_thompson5910 I got 20.5. are u sure that is it?
English is not my primary language... sry
i would go for the 0.55 since you want the partial sum, so i'm guessing that's a term.
you got the right answer, I'm getting 20.5 as well
Ok ughhh idk if i should put .55 or 20.5
because they want the nth PARTIAL sum
0.55 is the 20th term, there's no way it's the 20th partial sum
i make it 20.5
are u guys positive?
it's 20.5
yes
the only thing i'm not positive of is the question itself...
i am putting 20.5
partial sum is confusing
If you really really want, you can add up the terms 1.5+1.45+1.4+1.35+1.3+1.25+1.2+1.15+1.1+1.05+1+0.95+0.9+0.85+0.8+0.75+0.7+0.65+0.6+0.55 These are the first 20 terms And you'll get 20.5 So this confirms the answer.
thx
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