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Find exact value in radians: inverse tan of [tan(2pi/5)]?
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\[\tan^{-1} (\tan 2\pi/5)\]
yeah
wait i am solving.......
is 72 degrees the answer?
?
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no has to be in radians
i dont have the answer though
ok
its so simple the answer is 2pi/5
got it?
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im trying to come up with that, how do you end up with 2pi/5?
actually \[\tan^{-1} (\tan (\theta))=\theta \] provided \[\theta lies \between -\pi/2 \to \pi/2\]
provided theta lies between -pi/2 to pi/2
oh wow haha i cant believe i forgot that property
are you making fun of me or reminding yourself?
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no not at all im laughing at myself cause youre right it was so simple!
ok any other help required?
Nope that will be all, thanks!
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