Question

Describe the nature of the roots of the equation 2x^2 + 3x = –3.

Answer 1

\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
a=2
b=3
c=3
subtitution and solve

Answer 2

imaginary numbers

Answer 3

one real root
two real roots
two imaginary roots
cannot be determined

Answer 4

So C? two imaginary roots?

Answer 5

@Nancy_Lam

Answer 6

yeah

Answer 7

Thanks~

Answer 8

what about: 7x^2 = 4x + 1.

Answer 9

@sritama

Answer 10

two imaginary roots

Answer 11

How can you tell?

Answer 12

For ex: x^2 – 4x + 4 = 0. how would you tell for that one?

Answer 13

for the 2nd equation it is b

Answer 14

7x^2 = 4x + 1 , i mean

Answer 15

haha alright what about : x^2 – 4x + 4 = 0

Answer 16

two real roots,and they are same

Answer 17

x^2 – 4x + 4 = 0
(x-2)^2

Answer 18

all you have to get from the value of \[\sqrt{b^2-4ac}\]

Answer 19

Ohok. thanks!

Answer 20

So the root of hte discriminant.

Answer 21

if the value is negatives, roots are imaginary
if positive . roots are real
if 0,roots are real and same

Answer 22

yeah