Prove that the orthocentre of a triangle ABC with A(x1,y1), B(x2,y2) and C(x3,y3) is

(x1 tan A + x2 tan B + x3 tan C)/(tan A + tan B + tan C), (y1 tan A + y2 tan B + y3 tan C)/(tan A + tan B + tan C)

Please help

Question

Prove that the orthocentre of a triangle ABC with A(x1,y1), B(x2,y2) and C(x3,y3) is 

(x1 tan A + x2 tan B + x3 tan C)/(tan A + tan B + tan C), (y1 tan A + y2 tan B + y3 tan C)/(tan A + tan B + tan C)

Please help

vishweshshrimali5 · Answer

@satellite73

vishweshshrimali5 · Answer

@amistre64

vishweshshrimali5 · Answer

@Mertsj

vishweshshrimali5 · Answer

@lalaly

shubhamsrg · Answer

buddy it'll be a very long an tiring proof..am really sorry,,am too lazy..lol :P
keep on trying yourself,,you might just get it :)
even try an google over for some help..

vishweshshrimali5 · Answer

no prob.

mathslover · Answer

@shubhamsrg  can u give some steps so that i can also do this please

vishweshshrimali5 · Answer

@apoorvk

shubhamsrg · Answer

i dont know actually lol..
you want to know how to find orthocenter co-ordinate ?

shubhamsrg · Answer

use slope product thing,,or maybe something like that

vishweshshrimali5 · Answer

Thanks a lot friends I got my answer

shubhamsrg · Answer

even i guess this formulla will be in use :
tan x = (m1 - m2)/(1+ m1m2) where m1 m2 are slopes