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Mathematics 15 Online
OpenStudy (anonymous):

State the equivalent form of

OpenStudy (anonymous):

\[\frac{2}{3+i}\]

OpenStudy (anonymous):

\[a) \frac{3-i}{4}\] \[b) \frac{3-1}{5}\] \[c) \frac{4-i}{4}\] \[d) \frac{4-i}{5}\]

OpenStudy (anonymous):

I said a but I was wrong....it's suppose to be b....can anyone explain.

OpenStudy (anonymous):

2/(3+i)=2(3-i)/(3-i)(3+i)=2(3-i)/10=(3-i)/5

OpenStudy (anonymous):

(3-i)(3+i)=9-i^2=9-(-1)=10

OpenStudy (anonymous):

gotcha i forgot the -

OpenStudy (anonymous):

so you add the one instead of subtracting it

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

your welcome

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