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simplfy √1 ________________ (4-3i)-(2+5i)
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First combine the like terms in the denominator
(4-2)-(3I+5I)?
2-8i
Now multiply numerator and denominator by the conjugate of 2-8i which is 2+8i
\[\frac{1}{2-8i}\times \frac{2+8i}{2+8i}\]
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-4+i ______ 4????/
\[2+8i /4+64=2+8i/68=1/34+2/17i\]
\[\frac{2+8i}{4+64}=\frac{2+8i}{68}=\frac{1}{34}+\frac{2}{17}i\]
Yep. Good job.
;)
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